Q171 / 180 · KCET 2010 · Physics

The forbidden energy gap in $\mathrm{Ge}$ is $0.72 \mathrm{eV}$, Given, hc $=12400 \mathrm{eV}-Å$. The maximum wavelength of radiation that will generate electron hole pair is

  • A
    $172220 Å$
  • B
    $172.2 Å$
  • Correct answer
    C
    $17222 Å$
  • D
    $1722 Å$

Solution

Energy gap, $\mathrm{E}_{\mathrm{g}}=\frac{\mathrm{hc}}{\lambda}$ $$ \lambda=\frac{\mathrm{hc}}{\mathrm{E}_{\mathrm{g}}}=\frac{12400}{0.72}=17222 Å $$

Hence, the correct answer is option: 'C'.

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