Q24 / 160 · AP EAMCET 2025 (23 MAY SHIFT 2) · Chemistry

The following equation is obtained for a first order reaction at 300 K . $\log _{10} \frac{\mathrm{k}}{\mathrm{~A}}=0.00174$ What is the activation energy (in $\mathrm{J} \mathrm{mol}^{-1}$ ) of the reaction? $\left(\mathrm{R}=8.314 \mathrm{~J} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}\right)$

  • Correct answer
    A
    $10.0$
  • B
    $100.0$
  • C
    $0.1$
  • D
    $1.0$

Hence, the correct answer is option: 'A'.

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