Q50 / 181 · NTA Abhyas (JEE Main) 2020 · Physics · Laws of Motion

The figure below shows a block of mass M connected to an ideal string which passes through a thin fixed smooth pipe. On the other end, a particle of mass m is connected which revolves in a vertical circle of radius r. If the coefficient of friction between M and the surface is μ=23, then for what minimum value of M, the block of mass m can undergo complete vertical circular motion?

Figure

  • A
    Mmin=6m
  • Correct answer
    B
    Mmin=9m
  • C
    Mmin=3m
  • D
    Mmin=15m

Solution

For the particle to undergo complete vertical circular motion, its speed at the lowest point should be at least v=5gr. Also, the tension in the string is maximum when the particle is at the lowest point. The tension at the lowest position of the particle is

T=mg+mv2r

⇒T=mg+m5grr=6mg

The friction force acting on the block should be able to balance the maximum tension.

f=T=6mg

f=6mg≤μMg

⇒M≥6m23=9m

Mmin=9m

Hence, the correct answer is option: 'B'.

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