Q149 / 150 · MHT CET 2019 (Shift 2) · Physics

The excess of pressure, due to surface tension, on a spherical liquid drop of radius ‘R’ is proportional to

Correct answer
A
$R^{- 1}$
B
$R$
C
$R^{- 2}$
D
$R^{2}$

Solution

The excess of pressure due to surface tension on a spherically liquid drop is given by

p = \frac{2 T}{R}

….(i)
where, T = surface tension
and R = radius of liquid drop.
So, from Eq. (i), we get

p \propto \frac{1}{R} o r p \propto R^{- 1}

Hence, the correct answer is option: 'A'.

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