Q83 / 100 · BITSAT 2024 (Memory Based Paper 1) · Physics

The electrostatic force $\left(\overrightarrow{\mathrm{F}}_1\right)$ and magnetic force $\left(\overrightarrow{\mathrm{F}}_2\right)$ acting on a charge q moving with velocity v can be written:

  • A
    $\overrightarrow{\mathrm{F}}_1=\mathrm{q} \overrightarrow{\mathrm{V}} \cdot \overrightarrow{\mathrm{E}}, \overrightarrow{\mathrm{F}}_2=\mathrm{q}(\overrightarrow{\mathrm{B}} \cdot \overrightarrow{\mathrm{V}})$
  • B
    $\overrightarrow{\mathrm{F}}_1=\mathrm{q} \overrightarrow{\mathrm{B}}, \overrightarrow{\mathrm{F}}_2=\mathrm{q}(\overrightarrow{\mathrm{B}} \times \overrightarrow{\mathrm{V}})$
  • Correct answer
    C
    $\overrightarrow{\mathrm{F}}_1=\mathrm{q} \overrightarrow{\mathrm{E}}, \overrightarrow{\mathrm{F}}_2=\mathrm{q}(\overrightarrow{\mathrm{V}} \times \overrightarrow{\mathrm{B}})$
  • D
    $\overrightarrow{\mathrm{F}}_1=\mathrm{q} \overrightarrow{\mathrm{E}}, \overrightarrow{\mathrm{F}}_2=\mathrm{q}(\overrightarrow{\mathrm{B}} \times \overrightarrow{\mathrm{V}})$

Solution

Electrostatic force, $\overrightarrow{\mathrm{F}}_1=\mathrm{q} \overrightarrow{\mathrm{E}}$ Magnetic force, $\overrightarrow{\mathrm{F}}_2=\mathrm{q}(\overrightarrow{\mathrm{V}} \times \overrightarrow{\mathrm{B}})$

Hence, the correct answer is option: 'C'.

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