Q83 / 100 · BITSAT 2024 (Memory Based Paper 1) · Physics
The electrostatic force $\left(\overrightarrow{\mathrm{F}}_1\right)$ and magnetic force $\left(\overrightarrow{\mathrm{F}}_2\right)$ acting on a charge q moving with velocity v can be written:
- A$\overrightarrow{\mathrm{F}}_1=\mathrm{q} \overrightarrow{\mathrm{V}} \cdot \overrightarrow{\mathrm{E}}, \overrightarrow{\mathrm{F}}_2=\mathrm{q}(\overrightarrow{\mathrm{B}} \cdot \overrightarrow{\mathrm{V}})$
- B$\overrightarrow{\mathrm{F}}_1=\mathrm{q} \overrightarrow{\mathrm{B}}, \overrightarrow{\mathrm{F}}_2=\mathrm{q}(\overrightarrow{\mathrm{B}} \times \overrightarrow{\mathrm{V}})$
- Correct answerC$\overrightarrow{\mathrm{F}}_1=\mathrm{q} \overrightarrow{\mathrm{E}}, \overrightarrow{\mathrm{F}}_2=\mathrm{q}(\overrightarrow{\mathrm{V}} \times \overrightarrow{\mathrm{B}})$
- D$\overrightarrow{\mathrm{F}}_1=\mathrm{q} \overrightarrow{\mathrm{E}}, \overrightarrow{\mathrm{F}}_2=\mathrm{q}(\overrightarrow{\mathrm{B}} \times \overrightarrow{\mathrm{V}})$
Solution
Electrostatic force, $\overrightarrow{\mathrm{F}}_1=\mathrm{q} \overrightarrow{\mathrm{E}}$
Magnetic force, $\overrightarrow{\mathrm{F}}_2=\mathrm{q}(\overrightarrow{\mathrm{V}} \times \overrightarrow{\mathrm{B}})$
Hence, the correct answer is option: 'C'.