Q84 / 100 · BITSAT 2024 (Memory Based Paper 1) · Physics

A rectangular loop of length 2.5 m and width 2 m is placed at $60^{\circ}$ to a magnetic field of 4 T . The loop is removed from the field in 10 sec . The average emf induced in the loop during this time is

A
$-2 \mathrm{~V}$
B
$+2 \mathrm{~V}$
Correct answer
C
$+1 \mathrm{~V}$
D
$-1 \mathrm{~V}$

Solution

Averageemf, $\mathrm{e}=\frac{\text { Changein flux }}{\text { Time }}=-\frac{\Delta \phi}{\Delta \mathrm{t}}$ $=-\frac{0-\left(4 \times(2.5 \times 2) \cos 60^{\circ}\right)}{10}=+1 \mathrm{~V}$

Hence, the correct answer is option: 'C'.

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