Q19 / 250 · NTA Abhyas (NEET) 2020 · Physics · Electrostatics

The electric potential V at any point x, y, z in space is given by V=4x2 V. The electric field E (in Vm) at the point 1, 0, 2 is

  • A
    +8 in x direction
  • Correct answer
    B
    8 in -x direction
  • C
    16 in +x direction
  • D
    16 in -x direction

Solution

E=-dVdx=-ddx4x2, E=-8x

Hence, the correct answer is option: 'B'.

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