Q65 / 90 · JEE Main 2023 (11 Apr Shift 1) · Physics

The electric field in an electromagnetic wave is given as
E→=20sinωt-xcj→N C-1, where ω and c are angular frequency and velocity of electromagnetic wave respectively. The energy contained in a volume of 5×10-4 m3 will be
(Given ε0=8.85×10-12C2 N-1 m-2)

  • A
    88.5×10-13 J
  • B
    17.7×10-13 J
  • C
    28.5×10-13 J
  • Correct answer
    D
    8.85×10-13 J

Solution

Given that, E→=20sinωt-xcj→N C-1

The average energy density of an electromagnetic wave is 12ε0E20.

The total energy stored is 

Etotal =12ε0E02× volume

⇒Etotal=12×8.85×10-12×(20)2×5×10-4=8.85×10-13 J

Hence, the correct answer is option: 'D'.

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