Q71 / 75 · JEE Main 2025 (23 Jan Shift 2) · Physics
A time varying potential difference is applied between the plates of a parallel plate capacitor of capacitance $2.5 \mu \mathrm{~F}$. The dielectric constant of the medium between the capacitor plates is 1 . It produces an instantaneous displacement current of 0.25 mA in the intervening space between the capacitor plates, the magnitude of the rate of change of the potential difference will be _____ $\mathrm{Vs}^{-1}$.
Correct answer: 100
Solution
$\begin{aligned} & \frac{\mathrm{CdV}}{\mathrm{dt}}=\mathrm{I}_{\mathrm{d}} \\ & \frac{\mathrm{dV}}{\mathrm{dt}}=\frac{\mathrm{I}_{\mathrm{d}}}{\mathrm{C}} \\ & =\frac{0.25 \times 10^{-3}}{2.5 \times 10^{-6}} \\ & =100\end{aligned}$
Hence, the correct answer is 100.