Q155 / 160 · AP EAMCET 2022 (04 Jul Shift 2) · Physics

The electric field $(E)$ and magnetic field $(B)$ of an electromagnetic wave passing through vacuum are given by
$E = E_{0} \sin (k x - ω t)$
$B = B_{0} \sin (k x - ω t)$
Then the correct statement among the following is

Correct answer
A
$E_{0} k = B_{0} ω$
B
$E_{0} ω = B_{0} k$
C
$E_{0} B_{\circ} = ω k$
D
$E_{0} B_{0} = \frac{ω}{k}$

Solution

We know that the speed of a wave is given by,
$v = \frac{ω}{k} . . . (i)$
and the speed of the electromagnetic wave in vacuum is given by,
$c = \frac{E_{0}}{B_{0}} . . . (ii)$
So, the speed of the electromagnetic wave, using $(i)$ and $(ii)$ is,
$\frac{ω}{k} = \frac{E_{0}}{B_{0}}$
$\Rightarrow E_{0} k = B_{0} ω$ .

Hence, the correct answer is option: 'A'.

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The electric field E and magnetic field B of an electromagnetic wave passing through vacuum are given byE=E0sinkx-ωtB=B0sinkx-ωtThen the correct statement among the following is

Solution

Relevant Questions

The electric field $(E)$ and magnetic field $(B)$ of an electromagnetic wave passing through vacuum are given by
$E = E_{0} \sin (k x - ω t)$
$B = B_{0} \sin (k x - ω t)$
Then the correct statement among the following is