Q81 / 90 · JEE Main 2024 (05 Apr Shift 2) · Physics
The electric field at point $\mathrm{p}$ due to an electric dipole is $\mathrm{E}$. The electric field at point $\mathrm{R}$ on equitorial line will be $\frac{\mathrm{E}}{x}$. The value of $x$ :
Correct answer: 16
Solution
$\begin{aligned} & E_P=\frac{2 K P}{r^3}=E \\ & E_R=\frac{K P}{(2 r)^3}=\frac{E}{16} \\ & x=16\end{aligned}$
Hence, the correct answer is 16.