Q103 / 199 · NEET 2008 (Mains) · Physics
The distance travelled by a particle starting from rest and moving with an acceleration $\frac{4}{3} \mathrm{~ms}^{-2}$, in the third second is
- A$\frac{19}{3} m$
- B$6 \mathrm{~m}$
- C$4 \mathrm{~m}$
- Correct answerD$\frac{10}{3} m$
Solution
$$
S_{n t h}=u+\frac{a}{2}(2 n-1)
$$
Hence, the correct answer is option: 'D'.