Q104 / 199 · NEET 2008 (Mains) · Physics

A particle moves in a straight line with a constant acceleration. It changes its velocity from $10 \mathrm{~ms}^{-1}$ to $20 \mathrm{~ms}^{-1}$ while passing through a distance $135 \mathrm{~m}$ in t second. The value of $t$ is

Correct answer
A
9
B
10
C
1.8
D
12

Solution

$a=\frac{V_f^2-V_i^2}{2 S}, t=\frac{V_f-V_i}{a}$ or $S=\frac{1}{2}(u+v) t$

Hence, the correct answer is option: 'A'.

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