Q48 / 225 · JEE Main 2002 · Chemistry
The differential rate law for the reaction $\mathrm{H}_2+\mathrm{I}_2 \rightarrow 2 \mathrm{HI}$ is
- A$-\frac{\mathrm{d}\left[\mathrm{H}_2\right]}{\mathrm{dt}}=-\frac{\mathrm{d}\left[\mathrm{I}_2\right]}{\mathrm{dt}}=-\frac{\mathrm{d}[\mathrm{HI}]}{\mathrm{dt}}$
- B$\frac{\mathrm{d}\left[\mathrm{H}_2\right]}{\mathrm{dt}}=\frac{\mathrm{d}\left[\mathrm{I}_2\right]}{\mathrm{dt}}=\frac{1}{2} \frac{1 \mathrm{~d}[\mathrm{Hl}]}{\mathrm{dt}}$
- C$\frac{1}{2} \frac{\mathrm{d}\left[\mathrm{H}_2\right]}{\mathrm{dt}}=\frac{1}{2} \frac{\mathrm{d}\left[\mathrm{I}_2\right]}{\mathrm{dt}}=-\frac{\mathrm{d}[\mathrm{HI}]}{\mathrm{dt}}$
- Correct answerD$-2 \frac{\mathrm{d}\left[\mathrm{H}_2\right]}{\mathrm{dt}}=-2 \frac{\mathrm{d}\left[\mathrm{I}_2\right]}{\mathrm{dt}}=\frac{\mathrm{d}[\mathrm{HI}]}{\mathrm{dt}}$
Hence, the correct answer is option: 'D'.