Q18 / 116 · NTA Abhyas (JEE Main) 2020 · Physics · Ray Optics

The diagram shows a spherical surface which separates two media of refractive indices, μ1 and μ2, respectively. Now, a point object is placed on the principal axis as shown in the figure. Then

Figure

  • A
    Real image will form if μ1>μ2 and for all values of u
  • B
    Real image for some values of u if μ1>μ2
  • Correct answer
    C
    Virtual image will form if μ1>μ2
  • D
    Virtual image will form if μ1<μ2

Solution

μ2v-μ1-u=μ2-μ1R

⇒v=uRμ2uμ2-μ1-Rμ1

⇒v=uRμ2uμ2-μ1u+R

We can see that μ1>μ2 then image distance is negative which means virtual image

Hence, the correct answer is option: 'C'.

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