A thin prism of angle 5° made of glass of refractive index μ_1=1.5 is combined with another prism of glass of refractive index μ_2=1.75. The…

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A thin prism of angle 5° made of glass of refractive index μ_1=1.5 is combined with another prism of glass of refractive index μ_2=1.75. The combination of the prisms produces dispersion without deviation. The angle of the second prism should be

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Correct answer: (C) (10°)/3. For dispersion without deviation δ_1+δ_2=0 μ_1-1A⁡_1+μ_2-1A⁡_2=0 A⁡_2=-(μ_1-1A⁡_1)/(μ_2-1) Substituting the given values, we get A⁡_2=-(1·5-15°)/(1·75-1)=-(10°)/3 The negative sign shows that the two prisms must be joined in opposition.

A thin prism of angle $5 °$ made of glass of refractive index $μ_{1} = 1.5$ is combined with another prism of glass of refractive index $μ_{2} = 1.75$ . The combination of the prisms produces dispersion without deviation. The angle of the second prism should be

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A thin prism of angle 5° made of glass of refractive index μ1=1.5 is combined with another prism of glass of refractive index μ2=1.75. The combination of the prisms produces dispersion without deviation. The angle of the second prism should be

Solution

More Ray Optics Questions

A thin prism of angle $5 °$ made of glass of refractive index $μ_{1} = 1.5$ is combined with another prism of glass of refractive index $μ_{2} = 1.75$ . The combination of the prisms produces dispersion without deviation. The angle of the second prism should be