The degree of dissociation of 0.1 N CH_3COOH is (given K_a=1×10^(-5)) approximately _________

Correct answer: (D) 1×10^(-2). Concentration of solution, C=0.1 N Dissociation constant, K_(α)=1×10^(-5) We have to find out degree of dissociation, i.e, α K_(α)=Cα^2 ⇒α=√(K_(α)C) ⇒α=√(1×10^(-5)0.1)=1×10^(-2)

Q13 / 160 · TS EAMCET 2018 (04 May Shift 1) · Chemistry

The degree of dissociation of $0.1 N {CH}_{3} COOH$ is (given $K_{a} = 1 \times 10^{- 5}$ ) approximately _________

A
$1 \times 10^{- 6}$
B
$1 \times 10^{- 7}$
C
$1 \times 10^{- 3}$
Correct answer
D
$1 \times 10^{- 2}$

Solution

Concentration of solution, $C = 0.1 N$

Dissociation constant, $K_{α} = 1 \times 10^{- 5}$

We have to find out degree of dissociation, i.e, $α$

$K_{α} = {Cα}^{2}$

$\Rightarrow α = \sqrt{\frac{K_{α}}{C}}$

$\Rightarrow α = \sqrt{\frac{1 \times 10^{- 5}}{0.1}} = 1 \times 10^{- 2}$

Hence, the correct answer is option: 'D'.

Relevant Questions

The pH of pure water at 80 C is18 Jul, 2022 (M)Ionic Product of Water
The successive equilibrium constants for the stepwise dissociation of a tribasic acid are , and , respectively. The equilibrium constant for06 Aug, 2021 (M)Ionic Product of Water
Match the following List-1 Acid List-2 Ka(ionization constant) A) HCN I) 6 . 8 10 - 4 B) H 2 C 2 O 4 II) 8 . 9 10 - 8 C) H 2 S III) 4 . 9 1004 Aug, 2021 (M)Ionic Product of Water
If the molar concentrations of base and its conjugate acid are same, then pOH of the buffer solution is04 Aug, 2021 (M)Ionic Product of Water
At 25 o C , the ionization constant for anilinium hydroxide is 5 . 00 10 - 10 . The hydrolysis constant of anilinium chloride is09 Sep, 2020 (M)Ionic Product of Water
The concentration in of in is04 May, 2019 (E)Ionic Product of Water

The degree of dissociation of 0.1 N CH3COOH is (given Ka=1×10-5) approximately _________

Solution

Relevant Questions

The degree of dissociation of $0.1 N {CH}_{3} COOH$ is (given $K_{a} = 1 \times 10^{- 5}$ ) approximately _________