Q24 / 87 · NTA Abhyas (JEE Main) 2020 · Chemistry · Chemical Equilibrium

The degree of dissociation is 0.4 at 420 K and 1.0 atm for the gaseous reaction

PCl5g⟶PCl3g+Cl2(g) . Assuming ideal behavior of all gases, calculate the density of equilibrium mixture of equilibrium mixture at 420 K and 1.0 atm. (P = 31, Cl = 35.5)

  • Correct answer
    A
    4.30
  • B
    3.54
  • C
    2.64
  • D
    1.56

Solution

PCl 5 g ⇌ PCl 3 g + Cl 2 g t = 0 a 0 0 t eq 0.6a 0.4a 0.4a



nTotal=1.4a

∴   M av = 208 a 1.4 a              =148.57 ∴   P mix = P M av RT               = 1×148.57 0.0821×420 =4.30

Hence, the correct answer is option: 'A'.

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