Q23 / 87 · NTA Abhyas (JEE Main) 2020 · Chemistry · Chemical Equilibrium

For a reaction $A \to B, E_{a} = 10 kJ/mol, ΔH = 5 kJ/mol .$ Thus potential energy profile for this reaction is

A
Correct answer
B
C
D

Solution

Δ H = (E_{a})_{ƒ} - (E_{a})_{b}

5 = 10 - (E_{a})_{b}

{{(E}_{a})}_{b} = 5 kJ/mol .

(E_{a})_{ƒ} > (E_{a})_{b}

hence option

(B)

is correct

Hence, the correct answer is option: 'B'.

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