Q17 / 75 · JEE Main 2020 (03 Sep Shift 2) · Chemistry

The d-electron configuration of Ru(en)3Cl2, and FeH2O6Cl2 respectively are:

  • A
    t2g6eg0 and t2g6eg0
  • B
    t2g4eg2 and t2g6eg0
  • Correct answer
    C
    t2g6eg0 and t2g4eg2
  • D
    t2g4eg2 and t2g4eg2

Solution

Ruen3Cl2  ⇒ Ru2+=4d6=t2g6 , eg0

FeH2O62+ ⇒ Fe2+=3d6=t2g4 , eg2

Hence, the correct answer is option: 'C'.

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