The current in the $1 \Omega$ resistor shown in the circuit is

• A

  $\frac{2}{3} \mathrm{~A}$
• B

  $3 \mathrm{~A}$
• C

  $6 \mathrm{~A}$
• Correct answer
  D

  $2 \mathrm{~A}$

Solution

Two $4 \Omega$ resistors are in parallel combination. Their equivalent resistance $$ =\frac{4 \times 4}{4+4}=\frac{16}{8}=2 \Omega $$ $\therefore$ Total resistance of the
$$ \text { network }=2+1=3 \Omega $$ $\therefore$ Current through $1 \Omega$ resistor, $\mathrm{i}=\frac{6}{3}=2 \mathrm{~A}$

Hence, the correct answer is option: 'D'.