Q5 / 90 · JEE Main 2024 (08 Apr Shift 2) · Chemistry
The correct sequence of acidic strength of the following aliphatic acids in their decreasing order is: \(\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{COOH}, \mathrm{CH}_3 \mathrm{COOH}, \mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{COOH}, \mathrm{HCOOH}\)
- A\(\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{COOH} > \mathrm{CH}_3 \mathrm{CH}_2 \mathrm{COOH} > \mathrm{CH}_3 \mathrm{COOH} > \mathrm{HCOOH}\)
- B\(\mathrm{CH}_3 \mathrm{COOH} > \mathrm{CH}_3 \mathrm{CH}_2 \mathrm{COOH} > \mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{COOH} > \mathrm{HCOOH}\)
- Correct answerC\(\mathrm{HCOOH} > \mathrm{CH}_3 \mathrm{COOH} > \mathrm{CH}_3 \mathrm{CH}_2 \mathrm{COOH} > \mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{COOH}\)
- D\(\mathrm{HCOOH} > \mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{COOH} > \mathrm{CH}_3 \mathrm{CH}_2 \mathrm{COOH} > \mathrm{CH}_3 \mathrm{COOH}\)
Solution
$\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{COOH}, \mathrm{CH}_3 \mathrm{COOH}, \mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{COOH}$, $\mathrm{HCOOH}$
The correct order is :
$\begin{aligned} & \mathrm{HCOOH}>\mathrm{CH}_3 \mathrm{COOH}>\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{COOH}> \\ & \mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{COOH}\end{aligned}$
Hence, the correct answer is option: 'C'.