The correct match of the group reagents in List-I for precipitating the metal ion given in List-II from solutions, is

	LIST - I		LIST - II
(P)	Passing $\mathrm{H}_2 \mathrm{~S}$ in the presence of $\mathrm{NH}_4 \mathrm{OH}$	(1)	$\mathrm{Cu}^{2+}$
(Q)	$\left(\mathrm{NH}_4\right)_2 \mathrm{CO}_3$ in the presence of $\mathrm{NH}_4 \mathrm{OH}$	(2)	$\mathrm{Al}^{3+}$
(R)	$\mathrm{NH}_4 \mathrm{OH}$ in the presence of $\mathrm{NH}_4 \mathrm{Cl}$	(3)	$\mathrm{Mn}^{2+}$
(S)	Passing $\mathrm{H}_2 \mathrm{~S}$ in the presence of dilute HCl	(4)	$\mathrm{Ba}^{2+}$
		(5)	$\mathrm{Mg}^{2+}$

• Correct answer
  A

  $\mathrm{P} \rightarrow 3 ; \mathrm{Q} \rightarrow 4 ; \mathrm{R} \rightarrow 2 ; \mathrm{S} \rightarrow 1$
• B

  $\mathrm{P} \rightarrow 4 ; \mathrm{Q} \rightarrow 2 ; \mathrm{R} \rightarrow 3 ; \mathrm{S} \rightarrow 1$
• C

  $\mathrm{P} \rightarrow 3 ; \mathrm{Q} \rightarrow 4 ; \mathrm{R} \rightarrow 1 ; \mathrm{S} \rightarrow 5$
• D

  $\mathrm{P} \rightarrow 5 ; \mathrm{Q} \rightarrow 3 ; \mathrm{R} \rightarrow 2 ; \mathrm{S} \rightarrow 4$

Hence, the correct answer is option: 'A'.