Q3 / 54 · JEE Advanced 2020 (Paper 1) · Chemistry

A colorless aqueous solution contains nitrates of two metals, X and Y. When it was added to an aqueous solution of NaCl, a white precipitate was formed. This precipitate was found to be partly soluble in hot water to give a residue P and a solution Q. The residue P was soluble in aq. NH3 and also in excess sodium thiosulfate. The hot solution Q gave a yellow precipitate with KI. The metals X and Y, respectively, are

  • Correct answer
    A
    Ag and Pb
  • B
    Ag and Cd
  • C
    Cd and Pb
  • D
    Cd and Zn

Solution

X=AgNO3,  Y=PbNO32

AgNO3X+NaCl→AgCl(P) ↓+NaNO3

AgCl (s)↓(P)+2NH3→AgNH32+SolubleCl−

AgCl(P)+2Na2S2O3→Na3AgS2O32Solubel+NaCl

PbNO32Y+2NaCl→PbCl2White ppt Q(Soluble in hotwater)  ↓+2NaNO3 

PbCl2aq.Q+2KI→PbI2Yellow ppt+2KCl

Hence, the correct answer is option: 'A'.

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