Q23 / 90 · KVPY 2017 (19 Nov SB/SX) · Chemistry
The consecutive reaction $\mathrm{X} \rightarrow \mathrm{Y} \rightarrow \mathrm{Z}$ takes place in a closed container. Initially, the container has $\mathrm{A}_{0}$ moles of $\mathrm{X}$ (and no $\mathrm{Y}$ and $\mathrm{Z}$ ). The plot of total moles of the constituents in the container as a function of time will be
- A
- Correct answerB
- C
- D
Solution
$$
\begin{array}{llll}
& \mathrm{X} \longrightarrow & \mathrm{Y} \longrightarrow & \mathrm{Z} \\
\mathrm{t}=0 & \mathrm{~A}_{0} & 0 & 0 \\
\mathrm{t}=\mathrm{t} & \mathrm{A}_{0}-\mathrm{x} & \mathrm{y} & \mathrm{Z}
\end{array}
$$
So total moles of constituents will be more at any time ' $t^{\prime}$ as compared to $t=0$
Hence, the correct answer is option: 'B'.