Q14 / 97 · NTA Abhyas (JEE Main) 2020 · Chemistry · Solutions

The concentration in g/L of a solution of cane sugar (Molecular weight = 342) which is isotonic with a solution containing 6 g of urea (Molecular weight= 60) per litre is

  • A
    3.42
  • Correct answer
    B
    34.2
  • C
    5.7
  • D
    19

Solution

The two solution should have same molar concentration for being isotonic.
Molar concentration of cabe sugar = Molar concentration of urea  = 6 6 0 = 0.1  mol/L
concentration of cane sugar in g/L
= molar concentration × molecular weight
= 0.1 × 342 = 34.2

Hence, the correct answer is option: 'B'.

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