0.002 molal aqueous solution of an ionic compound with moleciular formula Co(NH_3 )_5 NO_2 Cl freezes at -0.00744^(∘)C . How many moles of ions does 3…

Question

0.002 molal aqueous solution of an ionic compound with moleciular formula Co(NH_3 )_5 NO_2 Cl freezes at -0.00744^(∘)C . How many moles of ions does 3 moles of the salt produce on being dissolved in water? [Given: K_f of water =1.86 K kg mol^(−1) ]

MARKS Content Team · Accepted Answer

Correct answer: 6. (ΔT_f ) = i × k_f × m (ΔT_f ) = i × k_f × Molality 0.00744 = i × 1.86 × 0.002 i≅2 ⇒i = 1 + α(n−1) ⇒2 = 1 + 1(n−1) ⇒n−1 = 1 ∴ n=2 ∴ number of ions produced from 3 moles of compound = 2×3=6

$0 .002$ molal aqueous solution of an ionic compound with moleciular formula ${Co(NH}_{3})_{5} ({NO}_{2}) Cl$ freezes at $- 0.0074 4^{\circ} C$ . How many moles of ions does $3$ moles of the salt produce on being dissolved in water?
[Given: $K_{f}$ of water $= 1.86 K kg {mol}^{- 1}$ ]

Solution

More Solutions Questions

0.002 molal aqueous solution of an ionic compound with moleciular formula Co(NH 3 ) 5 NO 2 Cl freezes at -0.00744∘C . How many moles of ions does 3 moles of the salt produce on being dissolved in water? [Given: K f of water =1.86 K kg mol −1 ]

Solution

More Solutions Questions

$0 .002$ molal aqueous solution of an ionic compound with moleciular formula ${Co(NH}_{3})_{5} ({NO}_{2}) Cl$ freezes at $- 0.0074 4^{\circ} C$ . How many moles of ions does $3$ moles of the salt produce on being dissolved in water?
[Given: $K_{f}$ of water $= 1.86 K kg {mol}^{- 1}$ ]