Q20 / 170 · Manipal (MET) 2015 · Chemistry
The coagulating power of an electrolyte for arsenious sulphide decrease in order
- A$\mathrm{Na}^{+}\gt\mathrm{Al}^{3+}\gt\mathrm{Ba}^{2+}$
- B$\mathrm{PO}_4^{3-}\gt\mathrm{SO}_4^{2-}\gt\mathrm{Cl}^{-}$
- C$\mathrm{Cl}^{-}\gt\mathrm{SO}_4^{2-}\gt\mathrm{Cl}^{-}$
- Correct answerD$\mathrm{Al}^{3+}\gt\mathrm{Ba}^{2+}\gt\mathrm{Na}^{+}$
Solution
Coagulating power of an electrolyte for arsenious sulphide decreases as $\mathrm{Al}^{3+}\gt\mathrm{Ba}^{2+}\gt\mathrm{Na}^{+}$
Hence, the correct answer is option: 'D'.