The circuit shown here is used to compare the EMFs of two cells ${\mathrm{E}}_1$ and ${\mathrm{E}}_2 \left({\mathrm{E}}_1>{\mathrm{E}}_2\right)$. The null point is at $\mathrm{C}$ when the galvanometer is connected to ${\mathrm{E}}_1$. When the galvanometer is connected to ${\mathrm{E}}_2$, the null point will be

• Correct answer
  A

  to the left of $\mathrm{C}$
• B

  to the right of $\mathrm{C}$
• C

  at $\mathrm{C}$ itself
• D

  nowhere on $\mathrm{A}\mathrm{B}$

Hence, the correct answer is option: 'A'.