Q35 / 256 · NTA Abhyas (NEET) 2020 · Physics · Current Electricity

A resistor of 6 kΩ with tolerance 10% and another resistance of 4 kΩ with tolerance 10% are connected in series. The tolerance of the combination is about

  • A
    5%
  • Correct answer
    B
    10%
  • C
    12%
  • D
    15%

Solution

In series combination

R=R1+R2

=6+4=10 kΩ

Error in combination,

ΔR=ΔR1+ΔR2

=10100×6+10100×4

=0.6+0.4=1

ΔRR=110

=10%

Hence, the correct answer is option: 'B'.

More Current Electricity Questions