Q125 / 125 · BITSAT 2013 · Physics

The circuit is equivalent to Figure

  • A
    AND gate
  • Correct answer
    B
    OR gate
  • C
    Not gate
  • D
    None of these

Solution

$\begin{aligned} \mathrm{Y} &=\mathrm{A}+(\overline{\mathrm{A}} \cdot \mathrm{B})=(\mathrm{A}+\overline{\mathrm{A}}) \cdot(\mathrm{A}+\mathrm{B}) \\ &=\mathrm{A}+\mathrm{B} \\ \Rightarrow & \mathrm{OR} \text { gate } \end{aligned}$

Hence, the correct answer is option: 'B'.

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