Q150 / 160 · WBJEE 2010 · Physics
The change in the gravitational potential energy when a body of mass $m$ is raised to a height $n \mathrm{R}$ above the surface of the Earth is (here $R$ is the radius of the Earth)
- Correct answerA$\left(\frac{n}{n+1}\right) m g \mathrm{R}$
- B$\left(\frac{n}{n-1}\right) m g \mathrm{R}$
- C$n m g R$
- D$\frac{m g R}{n}$
Solution
Hints: $\Delta \mathrm{U}=\frac{m g h}{1+\frac{h}{\mathrm{R}}}=\frac{m g \times n \mathrm{R}}{1+\frac{n \mathrm{R}}{\mathrm{R}}}=\frac{n m g \mathrm{R}}{n+1}$
Hence, the correct answer is option: 'A'.