A satellite of mass m rotates round the earth in a circular orbit of radius R. If the angular momentum of the satellite is J, then its kinetic energy (K) and the total energy (E) of the satellite are

• A

  $\mathrm{K}=\frac{\mathrm{J}^2}{m R^2}, \mathrm{E}=-\frac{\mathrm{J}^2}{2 m R^2}$
• Correct answer
  B

  $\mathrm{K}=\frac{\mathrm{J}^2}{2 m R^2}, \mathrm{E}=-\frac{\mathrm{J}^2}{2 m R^2}$
• C

  $\mathrm{K}=\frac{J^2}{2 m R^2}, \mathrm{E}=-\frac{J^2}{m R^2}$
• D

  $K=\frac{J^2}{2 m R^2}, E=\frac{J^2}{m R^2}$

Hence, the correct answer is option: 'B'.