Q62 / 180 · KCET 2008 · Mathematics

The centroid of the triangle $\mathrm{ABC}$, where $A \equiv(2,3), B \equiv(8,10)$ and $C \equiv(5,5)$ is

  • Correct answer
    A
    $(5,6)$
  • B
    $(6,5)$
  • C
    $(6,6)$
  • D
    $(15,18)$

Solution

Since, the vertices of the triangle are $A \equiv(2,3), B \equiv(8,10)$ and $C \equiv(5,5)$. $\therefore$ The centroid of $$ \Delta \mathrm{ABC}=\left(\frac{2+8+5}{3}, \frac{3+10+5}{3}\right)=(5,6) $$

Hence, the correct answer is option: 'A'.

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