Q62 / 180 · KCET 2008 · Mathematics
The centroid of the triangle $\mathrm{ABC}$, where $A \equiv(2,3), B \equiv(8,10)$ and $C \equiv(5,5)$ is
- Correct answerA$(5,6)$
- B$(6,5)$
- C$(6,6)$
- D$(15,18)$
Solution
Since, the vertices of the triangle are $A \equiv(2,3), B \equiv(8,10)$ and $C \equiv(5,5)$.
$\therefore$ The centroid of
$$
\Delta \mathrm{ABC}=\left(\frac{2+8+5}{3}, \frac{3+10+5}{3}\right)=(5,6)
$$
Hence, the correct answer is option: 'A'.