The centre of the circle passing through the points of intersection of the curves $\left(2x+3y+4\right)\left(3x+2y-1\right)=0$ and $xy=0$ is

• A

  ( $\frac{5}{6},-\frac{5}{12})$
• Correct answer
  B

  $\left(-\frac{5}{6},-\frac{5}{12}\right)$
• C

  $\left(\frac{5}{12},-\frac{5}{6}\right)$
• D

  $\left(-\frac{5}{12},\frac{5}{6}\right)$

Hence, the correct answer is option: 'B'.