Q131 / 160 · AP EAMCET 2020 (22 Sep Shift 2) · Physics

The capacity of parallel plate condenser is $5 \mu \mathrm{F}$. When a glass plate is placed between the plates of the condenser, its potential difference reduces to $1 / 8$ of the original value. The magnitude of relative dielectric constant of glass is

  • A
    4
  • B
    6
  • C
    7
  • Correct answer
    D
    8

Solution

Given, $C=5 \mu \mathrm{F}=5 \times 10^{-6} \mathrm{~F}$ Initial potential $=V$ When glass plate of dielectric constant $K$ is introduced between the plates of capacitor, then potential difference is $$ \begin{aligned} & V^{\prime} & =\frac{V}{8} \\ \therefore & K & =\frac{V}{V^{\prime}}=\frac{V}{V / 8} \\ \Rightarrow & K & =8 \end{aligned} $$

Hence, the correct answer is option: 'D'.

Relevant Questions