A capacitor of capacitance $2 \mu \mathrm{~F}$ is charged to 50 V and then disconected from the source. Later the gap between the plates of the capacitor is filled with a dielectric material. If the energy stored in the capacitor is decreased by $25 \%$ of its initial value, then the dielectric constant of the dieletric material is

• A

  $\frac{2}{3}$
• Correct answer
  B

  $\frac{4}{3}$
• C

  $\frac{3}{4}$
• D

  $\frac{3}{2}$

Hence, the correct answer is option: 'B'.