Q90 / 160 · JIPMER 2010 · Chemistry
The bond length of HCl bond is $2.29 \times 10^{-10} \mathrm{~m}$.
The percentage ionic character of HCl , if measured dipole moment is $6.226 \times 10^{-30} \mathrm{C}-\mathrm{m}$, is
- A$8 \%$
- B$20 \%$
- Correct answerC$17 \%$
- D$50 \%$
Solution
$\begin{aligned} & \mu_{\text {cal }}=e \times d=1.6 \times 10^{-19} \times 2.29 \times 10^{-10} \\ & =3.664 \times 10^{-29} \mathrm{C}-\mathrm{m} \\ & \begin{aligned} \% \text { ionic character } & =\frac{\mu_{\text {exp }}}{\mu_{\text {cal }}} \times 100 \\ & =\frac{6.226 \times 10^{-30}}{3.664 \times 10^{-29}} \times 100 \\ & =17 \%\end{aligned}\end{aligned}$
Hence, the correct answer is option: 'C'.