Q31 / 46 · NTA Abhyas (NEET) 2020 · Physics · Kinetic Theory of Gases

The average translational $K.E.$ in one millilitre volume of oxygen at $NTP$ is

Correct answer
A
$0.15 J$
B
$0.036 J$
C
$0.56 J$
D
$152 J$

Solution

{KE}_{trans} = \frac{3}{2} PV

{KE}_{trans} = \frac{3}{2} (10^{5}) (10^{- 6})

{KE}_{trans} = 0 .15 J

Hence, the correct answer is option: 'A'.

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