The area of the region bounded by the lines x=1, x=2, and the curves xy-e^x=sinx and 2xy=2sinx+x^3 is

Question

MARKS Content Team · Accepted Answer

Correct answer: (B) e^2-e-7/6. The area of region bounded by the curves xy-e^x=sinx or y=sinx/x+e^x and 2xy=2sinx+x^3 or y=sinx/x+x^22 between lines x=1 and x=2 is A=∫12sinx/x+e^x-sinx/x+x^22dx =∫12e^x-x^22dx=e^x-x^3612=e^2-e-7/6

The area of the region bounded by the lines $x = 1, x = 2$ , and the curves $x (y - e^{x}) = \sin x$ and $2 x y = 2 \sin x + x^{3}$ is

Solution

More Area Under Curves Questions

The area of the region bounded by the lines x=1, x=2, and the curves xy-ex=sinx and 2xy=2sinx+x3 is

Solution

More Area Under Curves Questions

The area of the region bounded by the lines $x = 1, x = 2$ , and the curves $x (y - e^{x}) = \sin x$ and $2 x y = 2 \sin x + x^{3}$ is