The area of the quadrilateral formed by the lines $x+2 y+3=0,2 x+4 y+9=0$, $x-2 y+3=0$ and $3 x-6 y+11=0$ is

• A

  $\frac{5}{12}$
• Correct answer
  B

  $\frac{1}{4}$
• C

  $\frac{3}{4}$
• D

  $\frac{7}{12}$

Hence, the correct answer is option: 'B'.