Q125 / 160 · TS EAMCET 2023 (12 May Shift 1) · Physics

The angular speed of a particle moving in a circular path is doubled. Then, the centripetal acceleration of the particle is

  • Correct answer
    A
    4 times the initial centripteal acceleration
  • B
    halved
  • C
    doubled
  • D
    unchanged

Solution

Angular speed, $\omega=2 \omega$ $\begin{aligned} & \frac{a_1}{a_2}=\frac{R \omega_1^2}{R \omega_2^2} \\ & \Rightarrow \frac{a_1}{a_2}=\frac{R \omega^2}{R(2 \omega)^2} \end{aligned}$ $\begin{aligned} & =\frac{\mathrm{R} \omega^2}{4 \mathrm{R} \omega^2}=\frac{1}{4} \\ & \because \mathrm{a}_2=4 \mathrm{a}_1\end{aligned}$

Hence, the correct answer is option: 'A'.

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