Q126 / 160 · TS EAMCET 2022 (19 Jul Shift 1) · Physics

A merry-go-round rotating at a constant angular speed completes 9 rotations in 18 seconds. What is its angular speed?

  • A
    $\pi / 2 \mathrm{rad} / \mathrm{s}$
  • Correct answer
    B
    $\pi \mathrm{rad} / \mathrm{s}$
  • C
    $2 \pi \mathrm{rad} / \mathrm{s}$
  • D
    $3 \pi \mathrm{rad} / \mathrm{s}$

Solution

$\begin{aligned} & 1 \text { rotation }=2 \pi \\ & \text { Angular speed }=\frac{\text { Change in angular rotaion }}{\text { Change in time }} \\ & =\frac{9 \times 2 \pi}{18}=\pi \mathrm{rad} / \mathrm{s}\end{aligned}$

Hence, the correct answer is option: 'B'.

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