Q52 / 180 · NEET 2015 (Phase 1) · Chemistry

The angular momentum of electron in $d$ -orbital is equal to

Correct answer
A
$\sqrt{6} ℏ$
B
$\sqrt{2} ℏ$
C
$2 \sqrt{3} ℏ$
D
$0 ℏ$

Solution

For

d

-electrons,

l = 2

.

Angular orbital momentum

= \sqrt{l (l + 1)} \frac{h}{2 π}

= \sqrt{6} \frac{h}{2 π} = \sqrt{6} ℏ

∴ \frac{h}{2 π} = ℏ

Hence, the correct answer is option: 'A'.

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