Q188 / 225 · JEE Main 2004 · Physics
The angle of incidence at which reflected light totally polarized for reflection from air to glass (refractive index $n$ ), is
- A$\sin ^{-1}(n)$
- B$\sin ^{-1}(1 / n)$
- C$\tan ^{-1}(1 / n)$
- Correct answerD$\tan ^{-1}(n)$
Solution
Brewster's law: According to this law the ordinary light is completely polarised in the plane of incidence when it gets reflected from transparent medium at a particular angle known as the angle of polarisation.
$$
\mathrm{n}=\tan \mathrm{i}_{\mathrm{p}}
$$
Hence, the correct answer is option: 'D'.