Q66 / 75 · JEE Main 2026 (23 January Shift 2) · Physics
When an unpolarized light falls at a particular angle on a glass plate (placed in air), it is observed that the reflected beam is linearly polarized. The angle of refracted beam with respect to the normal is $\_\_\_\_$.
$\left(\tan ^{-1}(1.52)=57.7^{\circ}\right.$, refractive indices of air and glass are 1.00 and 1.52, respectively.)
$\left(\tan ^{-1}(1.52)=57.7^{\circ}\right.$, refractive indices of air and glass are 1.00 and 1.52, respectively.)
- A$39.6^{\circ}$
- Correct answerB$32.3^{\circ}$
- C$36.3^{\circ}$
- D$42.6^{\circ}$
Solution

$\tan i = \dfrac{\mu_2}{\mu_1} = \dfrac{\mu_g}{\mu_a}$
$\tan i = 1.52$
$i = 57.7°$
$r = 90° - i$
$r = 32.3°$
Hence, the correct answer is option: 'B'.