Q10 / 46 · NTA Abhyas (JEE Main) 2020 · Physics · Motion In One Dimension

The acceleration experienced by a moving boat after is engine is cut-off, is given by a=-kv3, where k is a constant. If v0 is the magnitude of velocity at cut-off, then the magnitude of the velocity at time t after the cut off is

  • A
    v02ktv02
  • B
    v01+2 ktv02
  • C
    v01-2 k v02
  • Correct answer
    D
    v01+2 ktv02

Solution

Given, acceleration a=-kv3

Initial velocity at cut-off, v1=v0

Initial time of cut-off, t=0

And final time after cut-off, t2=t

Again, a=dvdt=-kv3

Or                     dvv3=-kdt

Integrating both sides, with in the condition of motion.

               ∫v0vdvv3=-∫0tk dt

Or     -12v2v0v=-kt0t

Or     12v2-12v02=kt

Or                   v=v01+2 kt v02

Hence, the correct answer is option: 'D'.

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