Q21 / 180 · KCET 2013 · Chemistry
Temperature coefficient of a reaction is 2 . When temperature is increased from $30^{\circ} \mathrm{C}$ to $90^{\circ} \mathrm{C}$, the rate of reaction is increased by
- A60 times
- Correct answerB64 times
- C150 times
- D400 times
Solution
Temperature coefficient
$(n)=\frac{\text { Rate constant at } T+10^{\circ} \mathrm{C}}{\text { Rate constant at } T^{\circ} \mathrm{C}}=2$
i.e., For each $10^{\circ} \mathrm{C}$ rise in temperature, rate becomes two times for the reaction
$\begin{array}{cc}\text { Temperature } & \text { Rate of reaction } \\ 30^{\circ} \mathrm{C} & R_{1} \\ 40^{\circ} \mathrm{C} & 2 R_{1} \\ 50^{\circ} \mathrm{C} & (2)^{2} R_{1} \\ 60^{\circ} \mathrm{C} & (2)^{3} R_{1} \\ 70^{\circ} \mathrm{C} & (2)^{4} R_{1} \\ 80^{\circ} \mathrm{C} & (2)^{5} R_{1} \\ 90^{\circ} \mathrm{C} & (2)^{6} R_{1}\end{array}$
$\therefore$ Rate of reacation at $90^{\circ} \mathrm{C}$ will become $(2)^{6}=64$ times.
Hence, the correct answer is option: 'B'.