Q52 / 180 · KCET 2018 · Chemistry
The temperature coefficient of a reaction is \( 2 \). When the temperature is increased from \( 30^{\circ} \mathrm{C} \) to
\( 90^{\circ} \mathrm{C} \), the rate of reaction is increased by
\( 90^{\circ} \mathrm{C} \), the rate of reaction is increased by
- A\( 150 \) times
- B\( 410 \) times
- C\( 72 \) times
- Correct answerD\( 64 \) times
Solution
Using the formula, \( \frac{K_{T_{2}}}{K_{T_{1}}}=\mu^{\Delta T / 10} \)
\[ =2^{\frac{90-30}{10}} \]
\[ =2^{6}=64 \text { times. } \]
\[ =2^{\frac{90-30}{10}} \]
\[ =2^{6}=64 \text { times. } \]
Hence, the correct answer is option: 'D'.