Q19 / 77 · NTA Abhyas (JEE Main) 2020 · Chemistry · Solid State

TlAlSO42 . xH2O is bcc with edge length ‘a’= 1.22 nm. If the density of the solid is 2.32 g/cc, then the value of x is
(Given: N A  = 6 ×  10 23 , atomtextc weight (in g/mol ) TI = 204, Al = 27, S = 32, O = 16, H = 1 )

  • A
    2
  • B
    4
  • Correct answer
    C
    47
  • D
    70

Solution

For any unit cell
d =  2 M a 3   N A (for BCC, Z = 2)
2.32=2 ×M6×1023×1.223×10–21
∴ M=1264
So 4 2 3 + x 1 8 = 1 2 6 4    
x = 4 7

Hence, the correct answer is option: 'C'.

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